使用日期格式（例如“ 10/12/2010”）更新具有特定年份的表中的记录？
要更新特定年份的记录，请使用YEAR()以下语法中的方法：
update yourTableName set yourColumnName1=yourValue1 where YEAR(str_to_date(yourColumnName2,'%d/%m/%Y'))=yourValue2;
让我们首先创建一个表-
mysql> create table DemoTable1924 ( UserName varchar(20), UserJoiningDate varchar(40) );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable1924 values('Chris','10/12/2010');
mysql> insert into DemoTable1924 values('David','20/01/2011');
mysql> insert into DemoTable1924 values('Mike','20/01/2010');
mysql> insert into DemoTable1924 values('Carol','26/04/2013');使用select语句显示表中的所有记录-
mysql> select * from DemoTable1924;
这将产生以下输出-
+----------+-----------------+ | UserName | UserJoiningDate | +----------+-----------------+ | Chris | 10/12/2010 | | David | 20/01/2011 | | Mike | 20/01/2010 | | Carol | 26/04/2013 | +----------+-----------------+ 4 rows in set (0.00 sec)
这是根据特定年份更新记录的查询-
mysql> update DemoTable1924 set UserName='Robert' where YEAR(str_to_date(UserJoiningDate,'%d/%m/%Y'))=2010; Rows matched: 2 Changed: 2 Warnings: 0
让我们再次检查表记录-
mysql> select * from DemoTable1924;
这将产生以下输出-
+----------+-----------------+ | UserName | UserJoiningDate | +----------+-----------------+ | Robert | 10/12/2010 | | David | 20/01/2011 | | Robert | 20/01/2010 | | Carol | 26/04/2013 | +----------+-----------------+ 4 rows in set (0.00 sec)