如何使用MySQL SELECT 1检查值是否存在?
为此,请使用SELECT1,如以下语法所示:
select 1 from yourTableName where yourColumnName=yourValue;
如果上面的返回1,则表示MySQL数据库中存在值。我们首先来看一个示例并创建一个表-
mysql> create table DemoTable ( StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, StudentName varchar(40), StudentAge int );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable(StudentName,StudentAge) values('Chris',21); mysql> insert into DemoTable(StudentName,StudentAge) values('David',20); mysql> insert into DemoTable(StudentName,StudentAge) values('Bob',22); mysql> insert into DemoTable(StudentName,StudentAge) values('Tom',19);
使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
这将产生以下输出-
+-----------+-------------+------------+ | StudentId | StudentName | StudentAge | +-----------+-------------+------------+ | 1 | Chris | 21 | | 2 | David | 20 | | 3 | Bob | 22 | | 4 | Tom | 19 | +-----------+-------------+------------+ 4 rows in set (0.00 sec)
现在让我们检查MySQL数据库中是否存在值-
mysql> select 1 from DemoTable where StudentName='Bob';
这将产生以下输出-
+---+ | 1 | +---+ | 1 | +---+ 1 row in set (0.00 sec)