C#判断一个String是否为数字类型
方案一：Try...Catch(执行效率不高)
privateboolIsNumberic(stringoText)
{
try
{
intvar1=Convert.ToInt32(oText);
returntrue;
}
catch
{
returnfalse;
}
}
方案二：正则表达式(推荐)
a)
publicstaticboolIsNumeric(stringvalue)
{
returnRegex.IsMatch(value,@"^[+-]?/d*[.]?/d*$");
}
publicstaticboolIsInt(stringvalue)
{
returnRegex.IsMatch(value,@"^[+-]?/d*$");
}
publicstaticboolIsUnsign(stringvalue)
{
returnRegex.IsMatch(value,@"^/d*[.]?/d*$");
}
b)
usingSystem; usingSystem.Text.RegularExpressions;
publicboolIsNumber(StringstrNumber) { RegexobjNotNumberPattern=newRegex("[^0-9.-]"); RegexobjTwoDotPattern=newRegex("[0-9]*[.][0-9]*[.][0-9]*"); RegexobjTwoMinusPattern=newRegex("[0-9]*[-][0-9]*[-][0-9]*"); StringstrValidRealPattern="^([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]+$"; StringstrValidIntegerPattern="^([-]|[0-9])[0-9]*$"; RegexobjNumberPattern=newRegex("("+strValidRealPattern+")|("+strValidIntegerPattern+")");
return!objNotNumberPattern.IsMatch(strNumber)&& !objTwoDotPattern.IsMatch(strNumber)&& !objTwoMinusPattern.IsMatch(strNumber)&& objNumberPattern.IsMatch(strNumber); }