微客导航 » 文章资讯 » 通过硬币翻转生成随机子集的 C++ 程序

通过硬币翻转生成随机子集的 C++ 程序

2023-06-20 09:41:03 184

这是一个通过硬币翻转生成随机子集的C++程序。

算法

Begin
   Take elements in an array as input.
   Using rand(), generate a random binary sequence.
   It generates randomly 0 or 1 as coin flipping and print the array element if it is 1.
End

示例

#include
#include
using namespace std;
int main() {
   int i, n;
   cout<<"\nEnter the number of elements: ";
   cin>>n;
   int a[n];
   cout<<"\n";
   for(i = 0; i < n; i++) {
      cout<<"Enter "<>a[i];
   }
   cout<<"\nThe random subset of the given set is: \n\t { ";
      for(i = 0; i < n; i++) {
         if(rand()%2 == 1)
            cout<输出结果Enter the number of elements: 7
Enter 1 element: 7
Enter 2 element: 6
Enter 3 element: 5
Enter 4 element: 4
Enter 5 element: 3
Enter 6 element: 2
Enter 7 element: 1
The random subset of the given set is:
{ 7 6 3 }

返回顶部
3162201930
czq8825@qq.com

通过硬币翻转生成随机子集的 C++ 程序

算法

示例

热门推荐

随机推荐