从给定的一组数字或字符中生成随机分区的 C++ 程序

2023-06-20 09:40:03 189

算法

Begin Take the integers or characters as input. For choice 1: Take the input of the n integer array. Assign l = 0 to traverse the array. Using rand(), generate random integer partition of n. For each partition i, print next i integer from index value l. For choice is 2: Take the input of a string in ch[]. Calculate the length of the string and assign l to 0, it will traverse the string. Generate random integer partition of the length of the string. For each partition i, print next i characters from index value l. End

示例

#include #include #include using namespace std; int main() { int n, i, j, l, c; cout<<"为整数输入1，为字符数组输入2以生成数组： "; cin>>c; //对于选择1： if(c== 1) { cout<<"\nEnter the number of element in the integer array: "; cin>>n; int a[n]; cout<<"\nEnter the elements of the array: \n"; for(i = 0; i < n; i++) { cout<<"Enter "<>a[i]; } cout<<"\nThe random partition of the given array is: \n"; l = 0; while(n > 0) { cout<<"\t["; i = rand()%n + 1; n = n-i; for(j = 0; j < i; j++) { cout<>ch; n = strlen(ch); cout<<"\nThe random partition of the given string is: \n"; l = 0; //分配l=0以遍历数组。 while(n > 0) { cout<<"\t[ "; i = rand()%n + 1; n = n-i; for(j = 0; j < i; j++) { cout<输出结果

为整数输入1，为字符数组输入2以生成数组： 1
Enter the number of element in the integer array: 10
Enter the elements of the array:
Enter 1 element: 10
Enter 2 element: 9
Enter 3 element: 8
Enter 4 element: 7
Enter 5 element: 6
Enter 6 element: 5
Enter 7 element: 4
Enter 8 element: 3
Enter 9 element: 2
Enter 10 element: 1
The random partition of the given array is:
[10 9 ] [8 7 6 5 ] [4 3 2 ] [1 ]

输出结果

为整数输入1，为字符数组输入2以生成数组： 2
输入字符： ABCDEFGHIJKLMNOPQRSTUVWXYZ

The random partition of the given string is:
[ A B C D E F G H I J K L M N O P ] [ Q R S T U V W X ] [ Y ] [ Z ]

从给定的一组数字或字符中生成随机分区的 C++ 程序

算法

示例

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