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查询将MySQL LIKE实现为MySQL IN？

2024-05-19 21:40:06 424

要实现类似MySQLIN()的查询，您需要使用COUNT()，IF()以及LIKE运算符。让我们首先创建一个表-

create table DemoTable
   -> (
   -> Subject varchar(80)
   -> );

使用插入命令在表中插入一些记录-

insert into DemoTable values('MySQLMongoDB');
insert into DemoTable values('MySQL');
insert into DemoTable values('JavaMySQL');
insert into DemoTable values('MongoDB');
insert into DemoTable values('Java');

使用select语句显示表中的所有记录-

select *from DemoTable;

这将产生以下输出-

+--------------+
| Subject      |
+--------------+
| MySQLMongoDB |
| MySQL        |
| JavaMySQL    |
| MongoDB      |
| Java         |
+--------------+
5 rows in set (0.00 sec)

这是将LIKE实现为IN()的查询-

select
   -> count(if(Subject like '%MySQL%',1,NULL)) as MySQLCount,
   -> count(if(Subject like '%Java%',1,NULL)) as JavaCount,
   -> count(if(Subject like '%MongoDB%',1,NULL)) as MongoDBCount
   -> from DemoTable;

这将产生以下输出-

+------------+-----------+--------------+
| MySQLCount | JavaCount | MongoDBCount |
+------------+-----------+--------------+
|          3 |         2 |            2 |
+------------+-----------+--------------+
1 row in set (0.00 sec)

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查询将MySQL LIKE实现为MySQL IN？

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