在C ++中通过指针传递Vs通过引用传递
这些是通过指针传递和通过引用传递的简单示例-
通过指针
#include <iostream>
using namespace std;
void swap(int* a, int* b) {
int c = *a;
*a= *b;
*b = c;
}
int main() {
int m = 7, n = 6;
cout << "Before Swap\n";
cout << "m = " << m << " n = " << n << "\n";
swap(&m, &n);
cout << "After Swap by pass by pointer\n";
cout << "m = " << m << " n = " << n << "\n";
}输出结果
Before Swap m = 7 n = 6 After Swap by pass by pointer m = 6 n = 7
通过引用
#include <iostream>
using namespace std;
void swap(int& a, int& b) {
int c = a;
a= b;
b = c;
}
int main() {
int m =7, n = 6;
cout << "Before Swap\n";
cout << "m = " << m << " n = " << n << "\n";
swap(m, n);
cout << "After Swap by pass by reference\n";
cout << "m = " << m << " n = " << n << "\n";
}输出结果
Before Swap m = 7 n = 6 After Swap by pass by reference m = 6 n = 7
因此，如果我们通过指针传递或引用传递参数给函数，它将产生相同的结果。唯一的区别是引用用于引用另一个名称中的现有变量，而指针用于存储变量的地址。使用引用是安全的，因为它不能为NULL。
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