根据JavaScript中的单词数组替换句子中所有出现的特定单词
我们需要编写一个包含字符串和字符串数组的JavaScript函数。
我们的函数应该返回一个新的字符串，该字符串中出现在数组中的单词的所有出现都由空格代替。
我们的函数应使用String.prototype.replace()方法来解决此问题。
示例
为此的代码将是-
var excludeWords = ["A", "ABOUT", "ABOVE", "ACROSS", "ALL", "ALONG", "AM",
"AN", "AND", "ANY", "ASK", "AT", "AWAY", "CAN", "DID", "DIDN'T", "DO",
"DON'T", "FOR", "FROM", "HAD", "HAS", "HER", "HIS", "IN", "INTO", "IS",
"IT", "NONE", "NOT", "OF", "ON", "One", "OUT", "SO", "SOME", "THAT",
"THE", "THEIR", "THERE", "THEY", "THESE", "THIS", "TO", "TWIT", "WAS",
"WERE", "WEREN'T", "WHICH", "WILL", "WITH", "WHAT", "WHEN", "WHY"];
var sentence = "The first solution does not work for any UTF-8 alphaben. I
have managed to create function which do not use RegExp and use good UTF-8
support in JavaScript engine. The idea is simple if symbol is equal in
uppercase and lowercase it is special character. The only exception is
made for whitespace.";
const removeExcludedWords = (str, words) => {
let sentence = '';
const regex = new RegExp(`\\b(${words.join('|')})\\b`, 'gi');
sentence = str.replace(regex, "");
return sentence;
};
console.log(removeExcludedWords(sentence, excludeWords));输出结果
控制台中的输出-
first solution does work UTF-8 alphaben. I have managed create function use RegExp use good UTF-8 support JavaScript engine. idea simple if symbol equal uppercase lowercase special character. only exception made whitespace.
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