Python Pandas - 返回一个包含来自 Index 对象的唯一值计数的系列，同时考虑 NaN 值
使用该方法返回包含来自Index对象的唯一值计数的系列，同时考虑NaN值。设置参数dropna值为假。index.value_counts()
首先，导入所需的库——
import pandas as pd import numpy as np
使用一些NaN值创建Pandas索引-
index = pd.Index([50, 10, 70, np.nan, 90, 50, np.nan, np.nan, 30])
显示熊猫指数-
print("Pandas Index...\n",index)使用的唯一值计数value_counts()。考虑NaN以及使用“dropna”参数的“False”值-
index.value_counts(dropna=False)
示例
以下是代码-
import pandas as pd
import numpy as np
#还使用一些NaN值创建Pandas索引
index = pd.Index([50, 10, 70, np.nan, 90, 50, np.nan, np.nan, 30])
#显示Pandas索引
print("Pandas Index...\n",index)
#返回索引中的元素数
print("\nNumber of elements in the index...\n",index.size)
#返回数据的dtype
print("\nThe dtype object...\n",index.dtype)
#使用value_counts()计算唯一值
# considering NaN as well using the "False" 的价值 "dropna" parameter
print("\nGet the count of unique values with NaN...\n",index.value_counts(dropna=False))输出结果这将产生以下输出-
Pandas Index... Float64Index([50.0, 10.0, 70.0, nan, 90.0, 50.0, nan, nan, 30.0], dtype='float64') Number of elements in the index... 9 The dtype object... float64 Get the count of unique values with NaN... NaN 3 50.0 2 10.0 1 70.0 1 90.0 1 30.0 1 dtype: int64