Python Pandas - 返回一个包含按升序排序的 Index 对象中唯一值计数的系列
要返回包含按升序排序的Index对象的唯一值计数的系列,请使用参数升序为True的方法。index.value_counts()
首先,导入所需的库——
import pandas as pd
创建熊猫索引-
index = pd.Index([50, 10, 70, 110, 90, 50, 110, 90, 30])
显示熊猫指数-
print("Pandas Index...\n",index)
按升序排序的唯一值计数-
print("\nGet the count of unique values sorted in ascending order..." "\n",index.value_counts(ascending=True))
示例
以下是代码-
import pandas as pd #创建Pandas索引 index = pd.Index([50, 10, 70, 110, 90, 50, 110, 90, 30]) #显示Pandas索引 print("Pandas Index...\n",index) #返回索引中的元素数 print("\nNumber of elements in the index...\n",index.size) #返回数据的dtype print("\nThe dtype object...\n",index.dtype) #按升序排序的唯一值的计数 print("\nGet the count of unique values sorted in ascending order..." "\n",index.value_counts(ascending=True))输出结果
这将产生以下输出-
Pandas Index... Int64Index([50, 10, 70, 110, 90, 50, 110, 90, 30], dtype='int64') Number of elements in the index... 9 The dtype object... int64 Get the count of unique values sorted in ascending order... 10 1 70 1 30 1 50 2 110 2 90 2 dtype: int64