Python Pandas - 返回索引中最小值的 int 位置
要返回索引中最小值的int位置，请使用方法。index.argmin()
首先，导入所需的库-
import pandas as pd
创建索引-
index = pd.Index([15, 25, 55, 10, 100, 70, 35, 40, 55])
显示索引-
print("Pandas Index...\n",index)获取索引中最小值的int位置-
print("\nGet the int position of the smallest value in the Index...\n",index.argmin())示例
以下是代码-
import pandas as pd
#创建索引
index = pd.Index([15, 25, 55, 10, 100, 70, 35, 40, 55])
#显示索引
print("Pandas Index...\n",index)
#返回基础数据形状的元组
print("\nA tuple of the shape of underlying data...\n",index.shape)
#返回索引中的元素数
print("\nNumber of elements in the index...\n",index.size)
#Index中最小值的int位置
print("\nGet the int position of the smallest value in the Index...\n",index.argmin())输出结果这将产生以下代码-
Pandas Index... Int64Index([15, 25, 55, 10, 100, 70, 35, 40, 55], dtype='int64') A tuple of the shape of underlying data... (9,) Number of elements in the index... 9 Get the int position of the smallest value in the Index... 3