Python Pandas - 以秒频率对 TimeDeltaIndex 执行地板操作
要以秒频率对TimeDeltaIndex执行地板操作，请使用方法。对于秒频率，使用值为'S'的freq参数。TimeDeltaIndex.floor()
首先，导入所需的库-
import pandas as pd
创建一个TimeDeltaIndex对象。我们已经使用'data'参数设置了类似timedelta的数据-
tdIndex = pd.TimedeltaIndex(data =['5 day 8h 20min 35us 45ns', '+17:42:19.999999', '7 day 3h 08:16:02.000055', '+22:35:25.999999'])
显示TimedeltaIndex-
print("TimedeltaIndex...\n", tdIndex)以秒频率对TimeDeltaIndex日期进行地板操作。对于秒频率，我们使用了“S”-
print("\nPerforming Floor operation with seconds frequency...\n",
tdIndex.floor(freq='S'))示例
以下是代码-
import pandas as pd
#CreateaTimeDeltaIndexobject
# We have set the timedelta-like data using the 'data' parameter
tdIndex = pd.TimedeltaIndex(data =['5 day 8h 20min 35us 45ns', '+17:42:19.999999',
'7 day 3h 08:16:02.000055', '+22:35:25.999999'])
#displayTimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
#ReturnadataframeofthecomponentsofTimeDeltas
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)
#FlooroperationonTimeDeltaIndexdatewithsecondsfrequency
# For seconds frequency, we have used 'S'
print("\nPerforming Floor operation with seconds frequency...\n",
tdIndex.floor(freq='S'))输出结果这将产生以下代码-
TimedeltaIndex... TimedeltaIndex(['5 days 08:20:00.000035045', '0 days 17:42:19.999999', '7 days 11:16:02.000055', '0 days 22:35:25.999999'], dtype='timedelta64[ns]', freq=None) The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 5 8 20 0 0 35 45 1 0 17 42 19 999 999 0 2 7 11 16 2 0 55 0 3 0 22 35 25 999 999 0 Performing Floor operation with seconds frequency... TimedeltaIndex(['5 days 08:20:00', '0 days 17:42:19', '7 days 11:16:02', '0 days 22:35:25'], dtype='timedelta64[ns]', freq=None)