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Python Pandas - 如何以每小时的频率对 DateTimeIndex 执行 ceil 操作

2024-05-20 18:51:07 372

要以每小时的频率对DateTimeIndex执行ceil操作，请使用方法。对于每小时频率，使用值为“H”的freq参数。DateTimeIndex.ceil()

首先，导入所需的库-

import pandas as pd

创建一个日期时间索引，周期为5，频率为分钟，即分钟-

datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='20min')

以每小时的频率对DateTimeIndex日期执行Ceil操作。对于每小时频率，我们使用了“H”-

print("\nPerforming ceil operation with hourly frequency...\n",
datetimeindex.ceil(freq='H'))

示例

以下是代码-

import pandas as pd

#DatetimeIndexwithperiod5andfrequencyasmini.e.minutes
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='20min')

#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)

#CeiloperationonDateTimeIndexdatewithhourlyfrequency
# For hourly frequency, we have used 'H'
print("\nPerforming ceil operation with hourly frequency...\n",
datetimeindex.ceil(freq='H'))

输出结果

这将产生以下代码-

DateTimeIndex...
DatetimeIndex(['2021-09-29 07:20:32.261811624+09:30',
'2021-09-29 07:40:32.261811624+09:30',
'2021-09-29 08:00:32.261811624+09:30',
'2021-09-29 08:20:32.261811624+09:30',
'2021-09-29 08:40:32.261811624+09:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='20T')
DateTimeIndex frequency...
<20 * Minutes>

Performing ceil operation with hourly frequency...
DatetimeIndex(['2021-09-29 08:00:00+09:30', '2021-09-29 08:00:00+09:30',
'2021-09-29 09:00:00+09:30', '2021-09-29 09:00:00+09:30',
'2021-09-29 09:00:00+09:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq=None)

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Python Pandas - 如何以每小时的频率对 DateTimeIndex 执行 ceil 操作

示例

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