逐元素检查 IntervalIndex 中的 Intervals 是否包含 Python Pandas 中的值
要返回与当前相同但在指定一侧关闭的IntervalArray，请使用set_closed()参数设置为both的方法。
首先，导入所需的库-
import pandas as pd
创建IntervalArray-
index = pd.arrays.IntervalArray.from_breaks(range(6))
显示间隔-
print("IntervalIndex...\n",index)返回一个与当前相同但在指定侧关闭的IntervalArray，即这里的“两者”-
print("\nResult...",index.set_closed('both'))示例
以下是代码-
import pandas as pd
#创建间隔数组
index = pd.arrays.IntervalArray.from_breaks(range(6))
#显示间隔
print("IntervalIndex...\n",index)
#显示间隔 length
print("\nIntervalIndex length...\n",index.length)
#左边界
print("\nThe left bound for the IntervalIndex...\n",index.left)
#正确的界限
print("\nThe right bound for the IntervalIndex...\n",index.right)
#返回一个与当前相同但在指定时间关闭的IntervalArray
# side i.e. "both" here
print("\nResult...",index.set_closed('both'))输出结果这将产生以下输出-
IntervalIndex... <IntervalArray> [(0, 1], (1, 2], (2, 3], (3, 4], (4, 5]] Length: 5, dtype: interval[int64, right] IntervalIndex length... Int64Index([1, 1, 1, 1, 1], dtype='int64') The left bound for the IntervalIndex... Int64Index([0, 1, 2, 3, 4], dtype='int64') The right bound for the IntervalIndex... Int64Index([1, 2, 3, 4, 5], dtype='int64') Result... <IntervalArray> [[0, 1], [1, 2], [2, 3], [3, 4], [4, 5]] Length: 5, dtype: interval[int64, both]