Python Pandas - 如何以秒频率对 DateTimeIndex 执行 ceil 操作
要以秒频率对DateTimeIndex执行ceil操作，请使用方法。对于秒频率，使用值为'S'的freq参数。DateTimeIndex.ceil()
首先，导入所需的库-
import pandas as pd
创建一个日期时间索引，周期为5，频率为S，即秒-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)以秒频率对DateTimeIndex日期执行Ceil操作。对于秒频率，我们使用了“S”-
print("\nPerforming ceil operation with seconds frequency...\n",
datetimeindex.ceil(freq='S'))示例
以下是代码-
import pandas as pd
#DatetimeIndexwithperiod5andfrequencyasSi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
#gettingthesecond
res = datetimeindex.second
#displayonlythesecond
print("\nThe second from DateTimeIndex...\n", res)
#CeiloperationonDateTimeIndexdatewithsecondsfrequency
# For seconds frequency, we have used 'S'
print("\nPerforming ceil operation with seconds frequency...\n",
datetimeindex.ceil(freq='S'))输出结果这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> The second from DateTimeIndex... Int64Index([32, 12, 52, 32, 12], dtype='int64') Performing ceil operation with seconds frequency... DatetimeIndex(['2021-10-18 07:20:33+10:30', '2021-10-18 07:21:13+10:30', '2021-10-18 07:21:53+10:30', '2021-10-18 07:22:33+10:30', '2021-10-18 07:23:13+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)