Python Pandas - 如何以每分钟的频率对 DateTimeIndex 执行地板操作
要以分钟频率对DateTimeIndex执行地板运算，请使用方法。对于每分钟频率，请使用值为'T'的freq参数。DateTimeIndex.floor()
首先，导入所需的库-
import pandas as pd
创建一个日期时间索引，周期为7，频率为s即秒-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)以分钟频率对DateTimeIndex日期进行地板操作。对于分钟频率，我们使用了“T”-
print("\nPerforming floor operation with minute frequency...\n",
datetimeindex.floor(freq='T'))示例
以下是代码-
import pandas as pd
#DatetimeIndexwithperiod7andfrequencyassi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
#displayDateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)
#gettingtheminute
res = datetimeindex.minute
#displayonlytheminute
print("\nThe minute from DateTimeIndex...\n", res)
#FlooroperationonDateTimeIndexdatewithminutefrequency
# For minute frequency, we have used 'T'
print("\nPerforming floor operation with minute frequency...\n",
datetimeindex.floor(freq='T'))输出结果这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> The minute from DateTimeIndex... Int64Index([20, 21, 21, 22, 23], dtype='int64') Performing floor operation with minute frequency... DatetimeIndex(['2021-10-18 07:20:00+10:30', '2021-10-18 07:21:00+10:30', '2021-10-18 07:21:00+10:30', '2021-10-18 07:22:00+10:30', '2021-10-18 07:23:00+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)