Python Pandas - 如何以每分钟的频率对 DateTimeIndex 执行地板操作
要以分钟频率对DateTimeIndex执行地板运算,请使用方法。对于每分钟频率,请使用值为'T'的freq参数。DateTimeIndex.floor()
首先,导入所需的库-
import pandas as pd
创建一个日期时间索引,周期为7,频率为s即秒-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='40S')
显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)
以分钟频率对DateTimeIndex日期进行地板操作。对于分钟频率,我们使用了“T”-
print("\nPerforming floor operation with minute frequency...\n", datetimeindex.floor(freq='T'))
示例
以下是代码-
import pandas as pd #DatetimeIndexwithperiod7andfrequencyassi.e.seconds #timezoneisAustralia/Adelaide datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='40S') #displayDateTimeIndex print("DateTimeIndex...\n", datetimeindex) #displayDateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) #gettingtheminute res = datetimeindex.minute #displayonlytheminute print("\nThe minute from DateTimeIndex...\n", res) #FlooroperationonDateTimeIndexdatewithminutefrequency # For minute frequency, we have used 'T' print("\nPerforming floor operation with minute frequency...\n", datetimeindex.floor(freq='T'))输出结果
这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> The minute from DateTimeIndex... Int64Index([20, 21, 21, 22, 23], dtype='int64') Performing floor operation with minute frequency... DatetimeIndex(['2021-10-18 07:20:00+10:30', '2021-10-18 07:21:00+10:30', '2021-10-18 07:21:00+10:30', '2021-10-18 07:22:00+10:30', '2021-10-18 07:23:00+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)