Python Pandas - 从 DateTimeIndex 创建一个 DataFrame 但覆盖结果列的名称
要从DateTimeIndex创建DataFrame，请使用.我们已经设置了name参数来覆盖结果列的名称。datetimeindex.to_frame()
首先，导入所需的库-
import pandas as pd
创建一个日期时间索引，周期为5，频率为S，即秒-
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')显示日期时间索引-
print("DateTimeIndex...\n", datetimeindex)未使用'False'参数在返回的DataFrame中设置原始索引。为了覆盖结果列的名称，我们使用了'name'参数-
print("\nDateTimeIndex to DataFrame...\n",
datetimeindex.to_frame(index=False, name = 'DateTimeData'))示例
以下是代码-
import pandas as pd
#DatetimeIndexwithperiod5andfrequencyasSi.e.seconds
#timezoneisAustralia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')
#displayDateTimeIndex
print("DateTimeIndex...\n", datetimeindex)
#displayDateTimeIndex frequency
print("\nDateTimeIndex frequency...\n", datetimeindex.freq)
#CreateaDataFramefromDateTimeIndex
# The original index isn't set in the returned DataFrame using the 'False' parameter
# To override the name of the resulting column, we have used the 'name' parameter
print("\nDateTimeIndex to DataFrame...\n",
datetimeindex.to_frame(index=False, name = 'DateTimeData'))输出结果这将产生以下代码-
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> DateTimeIndex to DataFrame... DateTimeData 0 2021-10-18 07:20:32.261811624+10:30 1 2021-10-18 07:21:12.261811624+10:30 2 2021-10-18 07:21:52.261811624+10:30 3 2021-10-18 07:22:32.261811624+10:30 4 2021-10-18 07:23:12.261811624+10:30