Python Pandas - 从 TimeDeltaIndex 对象创建一个 DataFrame 但覆盖结果列的名称
要从TimeDeltaIndex对象创建DataFrame，请使用TimeDeltaIndexto_frame()方法。使用name参数覆盖结果列的名称。
首先，导入所需的库-
import pandas as pd
创建一个TimeDeltaIndex对象。我们已经使用'data'参数设置了类似timedelta的数据-
tdIndex = pd.TimedeltaIndex(data =['4 day 8h 20min 35us 45ns', '+17:42:19.999999', '9 day 3h 08:16:02.000055', '+22:35:25.000075'])
显示TimedeltaIndex-
print("TimedeltaIndex...\n", tdIndex)从TimeDeltaIndex对象创建一个DataFrame。未使用'False'参数在返回的DataFrame中设置原始索引。为了覆盖结果列的名称，我们使用了'name'参数-
print("\nTimeDeltaIndex to DataFrame...\n", tdIndex.to_frame(index=False, name = 'DateTimeData'))示例
以下是代码-
import pandas as pd
#CreateaTimeDeltaIndexobject
# We have set the timedelta-like data using the 'data' parameter
tdIndex = pd.TimedeltaIndex(data =['4 day 8h 20min 35us 45ns', '+17:42:19.999999',
'9 day 3h 08:16:02.000055', '+22:35:25.000075'])
#displayTimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
#ReturnadataframeofthecomponentsofTimeDeltas
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)
#CreateaDataFramefromTimeDeltaIndexobject
# The original index isn't set in the returned DataFrame using the 'False' parameter
# To override the name of the resulting column, we have used the 'name' parameter
print("\nTimeDeltaIndex to DataFrame...\n", tdIndex.to_frame(index=False, name = 'DateTimeData'))输出结果这将产生以下代码-
TimedeltaIndex... TimedeltaIndex(['4 days 08:20:00.000035045', '0 days 17:42:19.999999', '9 days 11:16:02.000055', '0 days 22:35:25.000075'], dtype='timedelta64[ns]', freq=None) The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 4 8 20 0 0 35 45 1 0 17 42 19 999 999 0 2 9 11 16 2 0 55 0 3 0 22 35 25 0 75 0 TimeDeltaIndex to DataFrame... Date Time Data 0 4 days 08:20:00.000035045 1 0 days 17:42:19.999999 2 9 days 11:16:02.000055 3 0 days 22:35:25.000075