在C#中将指定的双精度浮点数转换为64位带符号整数
要将指定的双精度浮点数转换为64位带符号整数，代码如下-
示例
using System;
public class Demo {
public static void Main() {
double d = 5.646587687;
Console.Write("Value = "+d);
long res = BitConverter.DoubleToInt64Bits(d);
Console.Write("\n64-bit signed integer = "+res);
}
}输出结果
这将产生以下输出-
Value = 5.646587687 64-bit signed integer = 4618043510978159912
示例
让我们看另一个例子-
using System;
public class Demo {
public static void Main() {
double d = 0.001;
Console.Write("Value = "+d);
long res = BitConverter.DoubleToInt64Bits(d);
Console.Write("\n64-bit signed integer = "+res);
}
}输出结果
这将产生以下输出-
Value = 0.001 64-bit signed integer = 4562254508917369340