比较两个数组并获取与JavaScript不匹配的那些值
我们有两个包含一些公共值的文字数组，我们的工作是编写一个函数，该函数返回一个数组，其中包含两个数组中所有不常见的元素。
例如-
// if the two arrays are: const first = ['cat', 'dog', 'mouse']; const second = ['zebra', 'tiger', 'dog', 'mouse']; // then the output should be: const output = ['cat', 'zebra', 'tiger'] // because these three are the only elements that are not common to both arrays
让我们为此编写代码-
我们将散布两个数组并过滤结果数组，以获得不包含像这样的公共元素的数组-
示例
const first = ['cat', 'dog', 'mouse'];
const second = ['zebra', 'tiger', 'dog', 'mouse'];
const removeCommon = (first, second) => {
const spreaded = [...first, ...second];
return spreaded.filter(el => {
return !(first.includes(el) && second.includes(el));
})
};
console.log(removeCommon(first, second));输出结果
控制台中的输出将为-
[ 'cat', 'zebra', 'tiger' ]