如何在Java中使用Lambda表达式实现ObjIntConsumer接口？
ObjIntConsumer 接口是一种功能性 接口和在定义java.util.function包。该功能接口期望将一个对象-值 和整数-值 参数作为输入，并且不产生任何输出。它仅包含一种功能方法accept（Object，int）。
语法
@FunctionalInterface
public interface ObjIntConsumer {
void accept(T t, int value)
}在以下示例中，我们可以使用lambda 表达式实现ObjIntConsumer 接口。
示例1
import java.util.function.*;
public class ObjIntConsumerInterfaceTest1 {
public static void main(String args[]) {
ObjIntConsumer<String> objIntConsumberObj = (t, value) -> { // lambda expression if(t.length() > value) {
System.out.println("String is bigger than the expected value");
} else if(t.length() == value) {
System.out.println("String is equal to expected value");
} else {
System.out.println("String is shorter than the expected value");
}
}; // end of lambda expression objIntConsumberObj.accept("tutorialspoint.com", 15);
objIntConsumberObj.accept("tutorix.com", 15);
}
}输出结果
String is bigger than the expected value String is shorter than the expected value
示例2
import java.util.*;
import java.util.function.*;
public class ObjIntConsumerInterfaceTest2 {
public static void main(String args[]) {
ObjIntConsumer<List <Integer>> objIntConsumberObj = (t, value) -> { // lamnda expression if(t.contains(value)) {
System.out.println("Expected value is present in the string");
} else {
System.out.println("Expected value is not present in the string");
}
}; // end of lambda expression List<Integer> listObj = new ArrayList<Integer>();
listObj.add(55);
listObj.add(100);
listObj.add(75);
objIntConsumberObj.accept(listObj, 80);
objIntConsumberObj.accept(listObj, 100);
}
}输出结果
Expected value is not present in the string Expected value is present in the string