C#中的Decimal.ToDouble()方法
C#中的Decimal.ToDouble()方法用于将指定的Decimal的值转换为等效的双精度浮点数。
语法
以下是语法-
public static double ToDouble (decimal val);
上面的Val是要转换的十进制数。
示例
现在让我们看一个实现Decimal.ToDouble()方法的示例-
using System;
public class Demo {
public static void Main(){
Decimal val1 = -0.22m;
Decimal val2 = -0.01m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
Double res1 = Decimal.ToDouble(val1);
Double res2 = Decimal.ToDouble(val2);
Console.WriteLine("Double value1 (Decimal to Double) = "+res1);
Console.WriteLine("Double value2 (Decimal to Double) = "+res2);
}
}输出结果
这将产生以下输出-
Decimal 1 = -0.22 Decimal 2 = -0.01 Double value1 (Decimal to Double) = -0.22 Double value2 (Decimal to Double) = -0.01
示例
现在让我们来看另一个实现Decimal.ToDouble()方法的示例-
using System;
public class Demo {
public static void Main(){
Decimal val1 = 23828m;
Decimal val2 = 976587687595766665m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
Double res1 = Decimal.ToDouble(val1);
Double res2 = Decimal.ToDouble(val2);
Console.WriteLine("Double value1 (Decimal to Double) = "+res1);
Console.WriteLine("Double value2 (Decimal to Double) = "+res2);
}
}输出结果
这将产生以下输出-
Decimal 1 = 23828 Decimal 2 = 976587687595766665 Double value1 (Decimal to Double) = 23828 Double value2 (Decimal to Double) = 9.76587687595767E+17
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