首先根据值选择项目，然后根据日期对MySQL中其余记录进行排序
使用ORDERBY修复记录，然后显示
select * from yourTableName order by yourColumnName1=yourValue desc,yourColumnName2;
让我们首先创建一个表-
create table DemoTable1932 ( UserName varchar(20), ShippingDate date );
使用插入命令在表中插入一些记录-
insert into DemoTable1932 values('Chris','2018-10-12');
insert into DemoTable1932 values('David','2019-04-11');
insert into DemoTable1932 values('Mike','2016-12-04');
insert into DemoTable1932 values('Carol','2017-12-26');使用select语句显示表中的所有记录-
select * from DemoTable1932;
这将产生以下输出-
+----------+--------------+ | UserName | ShippingDate | +----------+--------------+ | Chris | 2018-10-12 | | David | 2019-04-11 | | Mike | 2016-12-04 | | Carol | 2017-12-26 | +----------+--------------+ 4 rows in set (0.00 sec)
这是查询以首先基于值选择项目，然后根据日期排序-
select * from DemoTable1932
order by UserName='David' desc,ShippingDate;这将产生以下输出-
+----------+--------------+ | UserName | ShippingDate | +----------+--------------+ | David | 2019-04-11 | | Mike | 2016-12-04 | | Carol | 2017-12-26 | | Chris | 2018-10-12 | +----------+--------------+ 4 rows in set (0.00 sec)