Java中AbstractSequentialList的containsAll()方法
AbstractSequentialList的containsAll()方法将检查此集合中的所有元素。如果所有此集合包含指定集合中的所有元素，即两个集合相同，则返回TRUE。
语法如下：
public boolean containsAll(Collection<?> c)
在这里，c是要检查的集合
要使用Java中的AbstractSequentialList类，您需要导入以下软件包：
import java.util.AbstractSequentialList;
以下是在Java中实现AbstractSequentialListcontainsAll()方法的示例：
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(66);
absSequential.add(99);
absSequential.add(140);
absSequential.add(270);
absSequential.add(360);
absSequential.add(490);
System.out.println("Elements in the AbstractSequentialList1 = "+absSequential);
AbstractSequentialList<Integer> absSequential2 = new LinkedList<>();
absSequential2.add(66);
absSequential2.add(99);
absSequential2.add(140);
absSequential2.add(270);
absSequential2.add(360);
absSequential2.add(490);
System.out.println("Elements in the AbstractSequentialList2 = "+absSequential2);
System.out.println("Both are same? = "+absSequential.containsAll(absSequential2));
}
}输出结果
Elements in the AbstractSequentialList1 = [66, 99, 140, 270, 360, 490] Elements in the AbstractSequentialList2 = [66, 99, 140, 270, 360, 490] Both are same? = true
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