在Java中，如何找到总和等于给定数字的连续子数组？
查找连续的子数组，其总和等于给定数-
遍历数组。
在每个元素上，将n个元素一个接一个地添加，当总和等于所需值时，打印子数组。
示例
import java.util.Arrays;
import java.util.Scanner;
public class sub_arrays {
public static void main(String args[]){
//Reading the array from the user
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the array that is to be created: ");
int size = sc.nextInt();
int[] myArray = new int[size];
System.out.println("Enter the elements of the array: ");
for(int i=0; i<size; i++){
myArray[i] = sc.nextInt();
}
//Reading the number
System.out.println("Enter the required sum: ");
int reqSum = sc.nextInt();
System.out.println("The array created is: "+Arrays.toString(myArray));
System.out.println("sub arrays whose sum is: "+reqSum);
for(int i=0; i<myArray.length; i++){
int sum = 0;
for (int j=i; j<myArray.length; j++){
sum = sum + myArray[j];
if(sum == reqSum){
System.out.println(Arrays.toString(Arrays.copyOfRange(myArray, i, j+1)));
}
}
}
}
}输出结果
Enter the size of the array that is to be created: 10 Enter the elements of the array: 5 4 1 2 3 4 1 4 5 5 Enter the required sum: 10 The array created is: [5, 4, 1, 2, 3, 4, 1, 4, 5, 5] sub arrays whose sum is: 10 [5, 4, 1] [4, 1, 2, 3] [1, 2, 3, 4] [2, 3, 4, 1] [1, 4, 5] [5, 5]