获取一个遍历C#中的StringDictionary的枚举数
为了获得一个通过StringDictionary进行迭代的枚举器，代码如下-
示例
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main() {
StringDictionary strDict1 = new StringDictionary();
strDict1.Add("A", "John");
strDict1.Add("B", "Andy");
strDict1.Add("C", "Tim");
strDict1.Add("D", "Ryan");
strDict1.Add("E", "Kevin");
strDict1.Add("F", "Katie");
strDict1.Add("G", "Brad");
Console.WriteLine("StringDictionary1 elements...");
foreach(DictionaryEntry de in strDict1) {
Console.WriteLine(de.Key + " " + de.Value);
}
StringDictionary strDict2 = new StringDictionary();
strDict2.Add("1", "A");
strDict2.Add("2", "B");
strDict2.Add("3", "C");
strDict2.Add("4", "D");
strDict2.Add("5", "E");
Console.WriteLine("\nStringDictionary2 key-value pairs...");
IEnumerator demoEnum = strDict2.GetEnumerator();
DictionaryEntry d;
while (demoEnum.MoveNext()) {
d = (DictionaryEntry)demoEnum.Current;
Console.WriteLine("Key = " + d.Key + ", Value = " + d.Value);
}
}
}输出结果
这将产生以下输出-
StringDictionary1 elements... a John b Andy c Tim d Ryan e Kevin f Katie g Brad StringDictionary2 key-value pairs... Key = 1, Value = A Key = 2, Value = B Key = 3, Value = C Key = 4, Value = D Key = 5, Value = E
示例
让我们看另一个例子-
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main() {
StringDictionary strDict = new StringDictionary();
strDict.Add("1", "One");
strDict.Add("2", "Two");
strDict.Add("3", "Three");
strDict.Add("4", "Four");
Console.WriteLine("StringDictionary key-value pairs...");
IEnumerator demoEnum = strDict.GetEnumerator();
DictionaryEntry d;
while (demoEnum.MoveNext()) {
d = (DictionaryEntry)demoEnum.Current;
Console.WriteLine("Key = " + d.Key + ", Value = " + d.Value);
}
}
}输出结果
这将产生以下输出-
StringDictionary key-value pairs... Key = 1, Value = One Key = 2, Value = Two Key = 3, Value = Three Key = 4, Value = Four