检查字符串的两个部分在 c # 中是否有相同的字符集
首先，设置要检查的字符串。
string s = "timetime";
现在为字符串的两半设置两个计数器。
int []one = new int[MAX_CHAR]; int []two = new int[MAX_CHAR];
检查字符串的两半。
for (int i = 0, j = l - 1; i < j; i++, j--) {
one[str[i] - 'a']++;
two[str[j] - 'a']++;
}以下是检查C#中字符串的两半是否具有相同字符集的完整代码。
示例
using System;
class Demo {
static int MAX_CHAR = 26;
static bool findSameCharacters(string str) {
int []one = new int[MAX_CHAR];
int []two = new int[MAX_CHAR];
int l = str.Length;
if (l == 1)
return true;
for (int i = 0, j = l - 1; i < j; i++, j--) {
one[str[i] - 'a']++;
two[str[j] - 'a']++;
}
for (int i = 0; i < MAX_CHAR; i++)
if (one[i] != two[i])
return false;
return true;
}
public static void Main() {
string str = "timetime";
if (findSameCharacters(str))
Console.Write("Yes: Two halves are same!");
else
Console.Write("No! Two halves are not same!");
}
}输出结果
Yes: Two halves are same!