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如何在单个MySQL查询中使用GROUP BY，HAVING和ORDER BY显示具有特定范围之和的记录？

2024-05-17 03:10:06 349

让我们首先创建一个表-

mysql> create table DemoTable
(
   Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   CustomerName varchar(20),
   ProductPrice int
);

使用插入命令在表中插入一些记录-

mysql> insert into DemoTable(CustomerName,ProductPrice) values('Chris',600);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('David',450);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Chris',980);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Mike',1200);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('Chris',400);
mysql> insert into DemoTable(CustomerName,ProductPrice) values('David',1200);

使用select语句显示表中的所有记录-

mysql> select *from DemoTable;

这将产生以下输出-

+----+--------------+--------------+
| Id | CustomerName | ProductPrice |
+----+--------------+--------------+
|  1 | Chris        |          600 |
|  2 | David        |          450 |
|  3 | Chris        |          980 |
|  4 | Mike         |         1200 |
|  5 | Chris        |          400 |
|  6 | David        |         1200 |
+----+--------------+--------------+
6 rows in set (0.00 sec)

以下是显示特定范围数字的查询-

mysql> select CustomerName,sum(ProductPrice) AS Total_Price
   from DemoTable
   group by CustomerName
   having sum(ProductPrice) between 1600 and 2000
   order by CustomerName DESC;

这将产生以下输出-

+--------------+-------------+
| CustomerName | Total_Price |
+--------------+-------------+
| David        |        1650 |
| Chris        |        1980 |
+--------------+-------------+
2 rows in set (0.00 sec)

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如何在单个MySQL查询中使用GROUP BY，HAVING和ORDER BY显示具有特定范围之和的记录？

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