用于检查给定的二叉树是否为AVL树的C ++程序

2024-05-15 05:05:44 482

Beginfunction AVL() returns true if the given tree is AVL otherwise false. if(root == NULL) return 1 leftheight = height(root->left) rightheight = height(root->right) if(abs(leftheight-rightheight) <= 1 && AVL(root->left) && AVL(root->right)) return 1 return 0 End

示例

#include <bits/stdc++.h> using namespace std; class nod { //node declaration public: int data; nod* l; nod* r; }; nod* newNod(int d) { //creation of new node nod* Nod = new nod(); Nod->data = d; Nod->l = NULL; Nod->r = NULL; return(Nod); } int max(int x, int y) { //return maximum between two values return (x >= y)? x: y; } int height(nod* node) { //get the height means the number of nodes along the longest path from the root node down to the farthest leaf node of the tree. if(node == NULL) return 0; return 1 + max(height(node->l), height(node->r)); } bool AVL(nod *root) { int lh; int rh; if(root == NULL) return 1; lh = height(root->l); // left height rh = height(root->r); // right height if(abs(lh-rh) <= 1 && AVL(root->l) && AVL(root->r)) return 1; return 0; } int main() { //将树的节点作为输入 nod *root = newNod(7); root->l = newNod(6); root->r = newNod(12); root->l->l = newNod(4); root->l->r = newNod(5); root->r->r = newNod(13); if(AVL(root)) cout << "The Tree is AVL Tree"<<endl; else cout << "The Tree is not AVL Tree "<<endl; nod *root1 = newNod(7); root1->l = newNod(6); root1->r = newNod(12); root1->l->l = newNod(4); root1->l->r = newNod(5); root1->r->r = newNod(13); root1->r->r->r = newNod(26); if(AVL(root1)) cout << "The Tree is AVL Tree"<<endl; else cout << "The Tree is not AVL Tree "<<endl; return 0; }

输出结果

The Tree is AVL Tree The Tree is not AVL Tree

用于检查给定的二叉树是否为AVL树的C ++程序

算法

示例

随机推荐

用于检查给定的二叉树是否为AVL树的C ++程序

算法

示例

热门推荐

随机推荐