Java中的LocalDateTime compareTo()方法
可以使用compareTo()Java中LocalDateTime类中的方法比较两个LocalDateTime对象。此方法需要单个参数，即要比较的LocalDateTime对象。
如果第一个LocalDateTime对象大于第二个LocalDateTime对象，则返回正数；如果第一个LocalDateTime对象小于第二个LocalDateTime对象，则返回负数；如果两个LocalDateTime对象相等，则返回零。
演示此的程序如下所示-
示例
import java.time.*;
public class Main {
public static void main(String[] args) {
LocalDateTime ldt1 = LocalDateTime.parse("2019-02-15T11:37:12");
LocalDateTime ldt2 = LocalDateTime.parse("2019-02-18T23:15:30");
System.out.println("The first LocalDateTime object is: " + ldt1);
System.out.println("The second LocalDateTime object is: " + ldt2);
int val = ldt1.compareTo(ldt2);
if(val > 0)
System.out.println("\nThe first LocalDateTime object is greater than the second LocalDateTime object");
else if(val < 0)
System.out.println("\nThe first LocalDateTime object is lesser than the second LocalDateTime object");
else
System.out.println("\nThe LocalDateTime objects are equal");
}
}输出结果
The first LocalDateTime object is: 2019-02-15T11:37:12 The second LocalDateTime object is: 2019-02-18T23:15:30 The first LocalDateTime object is lesser than the second LocalDateTime object
现在让我们了解上面的程序。
首先，显示两个LocalDateTime对象。然后使用compareTo()方法比较它们，并使用ifelse语句显示结果。演示这的代码片段如下-
LocalDateTime ldt1 = LocalDateTime.parse("2019-02-15T11:37:12");
LocalDateTime ldt2 = LocalDateTime.parse("2019-02-18T23:15:30");
System.out.println("The first LocalDateTime object is: " + ldt1);
System.out.println("The second LocalDateTime object is: " + ldt2);
int val = ldt1.compareTo(ldt2);
if(val > 0)
System.out.println("\nThe first LocalDateTime object is greater than the second LocalDateTime object");
else if(val < 0)
System.out.println("\nThe first LocalDateTime object is lesser than the second LocalDateTime object");
else
System.out.println("\nThe LocalDateTime objects are equal");