Java AbstractSequentialList的toArray（T []）方法
toArray()和toArray（T[]arr）之间的区别在于，这两种方法都返回包含此集合中所有元素的数组，但是后者具有一些其他功能，即，返回数组的运行时类型是指定数组的运行时类型。
语法如下：
public <T> T[] toArray(T[] arr)
在此，arr是要将此集合的元素存储到的数组，
要使用Java中的AbstractSequentialList类，您需要导入以下软件包：
import java.util.AbstractSequentialList;
以下是toArray()在Java中实现AbstractSequentialList方法的示例：
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(210);
absSequential.add(290);
absSequential.add(350);
absSequential.add(490);
absSequential.add(540);
absSequential.add(670);
absSequential.add(870);
System.out.println("Elements in the AbstractSequentialList = "+absSequential);
Integer[] strArr = new Integer[5];
strArr = absSequential.toArray(strArr);
System.out.println("Array = ");
for (int i = 0; i < strArr.length; i++)
System.out.println(strArr[i]); ;
}
}输出结果
Elements in the AbstractSequentialList = [210, 290, 350, 490, 540, 670, 870] Array = 210 290 350 490 540 670 870
让我们看另一个示例，其中数组大小大于元素总数：
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(210);
absSequential.add(290);
absSequential.add(350);
absSequential.add(490);
System.out.println("Elements in the AbstractSequentialList = "+absSequential);
Integer[] strArr = new Integer[7];
strArr = absSequential.toArray(strArr);
System.out.println("Array = ");
for (int i = 0; i < strArr.length; i++)
System.out.println(strArr[i]); ;
}
}输出结果
Elements in the AbstractSequentialList = [210, 290, 350, 490] Array = 210 290 350 490 null null null