有没有办法以更好的格式查看MongoDB结果？
是的，您可以使用findOne()。以下是语法-
db.yourCollectionName.findOne();
您也可以使用toArray()-
db.yourCollectionName.find().toArray();
首先让我们创建一个包含文档的集合-
> db.betterFormatDemo.insertOne({"StudentName":"Adam Smith","StudentScores":[98,67,89]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7ab826d78f205348bc640")
}
> db.betterFormatDemo.insertOne({"StudentName":"John Doe","StudentScores":[67,89,56]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7ab936d78f205348bc641")
}
> db.betterFormatDemo.insertOne({"StudentName":"Sam Williams","StudentScores":[45,43,33]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd7aba76d78f205348bc642")
}以下是在find()方法的帮助下显示集合中所有文档的查询-
> db.betterFormatDemo.find();
这将产生以下输出-
{ "_id" : ObjectId("5cd7ab826d78f205348bc640"), "StudentName" : "Adam Smith", "StudentScores" : [ 98, 67, 89 ] }
{ "_id" : ObjectId("5cd7ab936d78f205348bc641"), "StudentName" : "John Doe", "StudentScores" : [ 67, 89, 56 ] }
{ "_id" : ObjectId("5cd7aba76d78f205348bc642"), "StudentName" : "Sam Williams", "StudentScores" : [ 45, 43, 33 ] }情况1-使用findOne()。
以下是查询以更好的格式显示MongoDB结果-
> db.betterFormatDemo.findOne();
这将产生以下输出-
{
"_id" : ObjectId("5cd7ab826d78f205348bc640"),
"StudentName" : "Adam Smith",
"StudentScores" : [
98,
67,
89
]
}情况2-使用find().toArray()。
以下是查询以更好的格式显示MongoDB结果-
> db.betterFormatDemo.find().toArray();
这将产生以下输出-
[
{
"_id" : ObjectId("5cd7ab826d78f205348bc640"),
"StudentName" : "Adam Smith",
"StudentScores" : [
98,
67,
89
]
},
{
"_id" : ObjectId("5cd7ab936d78f205348bc641"),
"StudentName" : "John Doe",
"StudentScores" : [
67,
89,
56
]
},
{
"_id" : ObjectId("5cd7aba76d78f205348bc642"),
"StudentName" : "Sam Williams",
"StudentScores" : [
45,
43,
33
]
}
]