Java中的NavigableMap pollLastEntry()方法
NavigableMappollLastEntry()方法删除并返回与此映射中的最大键关联的键值映射。
让我们首先创建一个NavigableMap并向其中添加一些元素-
NavigableMap<Integer, String> n = new TreeMap<Integer, String>(); n.put(5, "Tom"); n.put(9, "John"); n.put(14, "Jamie"); n.put(1, "Tim"); n.put(4, "Jackie"); n.put(15, "Kurt"); n.put(19, "Tiger"); n.put(24, "Jacob");
现在，使用以下方法-
n.pollLastEntry();
以下是实现pollLastEntry()方法的示例-
示例
import java.util.*;
public class Demo {
public static void main(String[] args) {
NavigableMap<Integer, String> n = new TreeMap<Integer, String>();
n.put(5, "Tom");
n.put(9, "John");
n.put(14, "Jamie");
n.put(1, "Tim");
n.put(4, "Jackie");
n.put(15, "Kurt");
n.put(19, "Tiger");
n.put(24, "Jacob");
System.out.println("NavigableMap elements...\n"+n);
System.out.println("\nRemoved (last) key-value is "+n.pollLastEntry());
System.out.println("\nUpdated NavigableMap elements...\n"+n);
}
}输出结果
NavigableMap elements...
{1=Tim, 4=Jackie, 5=Tom, 9=John, 14=Jamie, 15=Kurt, 19=Tiger, 24=Jacob}
Removed (last) key-value is 24=Jacob
Updated NavigableMap elements...
{1=Tim, 4=Jackie, 5=Tom, 9=John, 14=Jamie, 15=Kurt, 19=Tiger}