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如何在MySQL中的两个日期之间查询？

2024-05-10 09:41:04 480

您可以借助BETWEEN语句在日期之间查询。语法如下-

select *from yourTableName where yourColumnName between ‘yourStartingDate’ and curdate().

使用curdate()或now()，这两个功能都将起作用。要了解上述语法，让我们创建一个表-

mysql> create table BetweenDateDemo
   −> (
   −> StartDate datetime
   −> );

在以下查询的帮助下在表中插入一些记录-

mysql> insert into BetweenDateDemo values(date_add(now(),interval -1 year));

mysql> insert into BetweenDateDemo values(date_add(now(),interval -2 year));

mysql> insert into BetweenDateDemo values(date_add(now(),interval -3 year));

mysql> insert into BetweenDateDemo values(date_add(now(),interval 1 year));

mysql> insert into BetweenDateDemo values(date_add(now(),interval 2 year));

mysql> insert into BetweenDateDemo values(date_add(now(),interval 3 year));

现在，您可以在select语句的帮助下显示表中的所有记录。查询如下-

mysql> select *from BetweenDateDemo;

以下是输出-

+---------------------+
| StartDate           |
+---------------------+
| 2017-12-08 11:45:47 |
| 2016-12-08 11:45:56 |
| 2015-12-08 11:46:01 |
| 2019-12-08 11:46:05 |
| 2020-12-08 11:46:11 |
| 2021-12-08 11:46:15 |
+---------------------+
6 rows in set (0.00 sec)

现在使用上面讨论的语法在日期之间执行选择-

mysql> select *from BetweenDateDemo where StartDate between '2014-8-12' and curdate();

以下是输出-

+---------------------+
| StartDate           |
+---------------------+
| 2017-12-08 11:45:47 |
| 2016-12-08 11:45:56 |
| 2015-12-08 11:46:01 |
+---------------------+
3 rows in set (0.00 sec)

使用ORDERBY获取排序顺序。查询如下-

mysql> select *from BetweenDateDemo where StartDate between '2014-8-12' and curdate() order by StartDate;

以下是输出-

+---------------------+
| StartDate           |
+---------------------+
| 2015-12-08 11:46:01 |
| 2016-12-08 11:45:56 |
| 2017-12-08 11:45:47 |
+---------------------+
3 rows in set (0.00 sec)

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如何在MySQL中的两个日期之间查询？

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