Java Integer compareTo()方法
java.lang.Integer.compareTo()方法以数字方式比较两个Integer对象。如果此Integer等于参数Integer，则此方法返回值0；如果此Integer在数值上小于参数Integer，则返回值小于0；如果此Integer在数值上大于参数Integer，则返回值大于0。
首先，设置两个Integer对象-
Integer obj1 = new Integer("100");
Integer obj2 = new Integer("200");现在，比较那些对象-
int res = obj1.compareTo(obj2);
以下是compareTo()在Java中实现该方法的示例-
示例
public class Main {
public static void main(String[] args) {
Integer obj1 = new Integer("100");
Integer obj2 = new Integer("200");
int res = obj1.compareTo(obj2);
if(retval > 0) {
System.out.println("obj1 is greater than obj2");
} else if(retval < 0) {
System.out.println("obj1 is less than obj2");
} else {
System.out.println("obj1 is equal to obj2");
}
}
}输出结果
obj1 is less than obj2