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MySQL Order通过特定的字符串？

2024-05-02 17:05:03 339

使用FIELD()函数通过选择所需的字符串进行排序。语法如下-

SELECT *FROM yourTableName
ORDER BY FIELD(yourColumnName,’yourValue1’, ’yourValue2’,’yourValue3’,....N);

为了理解上述语法，让我们创建一个表。创建表的查询如下-

mysql> create table OrderByListOfStrings
   -> (
   -> Id int not null auto_increment,
   -> CarName varchar(20),
   -> PRIMARY KEY(Id)
   -> );

使用insert命令在表中插入一些记录。查询如下-

mysql> insert into OrderByListOfStrings(CarName) values('Ford');

mysql> insert into OrderByListOfStrings(CarName) values('Audi');

mysql> insert into OrderByListOfStrings(CarName) values('Honda');

mysql> insert into OrderByListOfStrings(CarName) values('Aston Martin');

mysql> insert into OrderByListOfStrings(CarName) values('Bugatti');

mysql> insert into OrderByListOfStrings(CarName) values('BMW');

使用select语句显示表中的所有记录。查询如下-

mysql> select *from OrderByListOfStrings;

以下是输出-

+----+--------------+
| Id | CarName      |
+----+--------------+
|  1 | Ford         |
|  2 | Audi         |
|  3 | Honda        |
|  4 | Aston Martin |
|  5 | Bugatti      |
|  6 | BMW          |
+----+--------------+
6 rows in set (0.00 sec)

这是通过选择字符串来获取顺序的查询。设置任何您想要的顺序-

mysql> select *from OrderByListOfStrings
   -> order by field(CarName,'Bugatti','BMW','Audi','Aston Martin','Ford','Honda');

以下是重新排列使用field()方法设置的字符串的输出-

+----+--------------+
| Id | CarName      |
+----+--------------+
|  5 | Bugatti      |
|  6 | BMW          |
|  2 | Audi         |
|  4 | Aston Martin |
|  1 | Ford         |
|  3 | Honda        |
+----+--------------+
6 rows in set (0.00 sec)

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MySQL Order通过特定的字符串？

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