C ++程序使用运算符重载减去复数
可以使用C++中的大多数内置运算符来完成运算符重载。重载的运算符是带有关键字operator的函数，后跟定义的运算符。重载的运算符具有返回类型和类似任何函数的参数列表。
使用运算符重载减去复数的程序如下-
示例
#include<iostream>
using namespace std;
class ComplexNum {
private:
int real, imag;
public:
ComplexNum(int r = 0, int i =0) {
real = r;
imag = i;
}
ComplexNum operator - (ComplexNum const &obj1) {
ComplexNum obj2;
obj2.real = real - obj1.real;
obj2.imag = imag - obj1.imag;
return obj2;
}
void print() {
if(imag>=0)
cout << real << " + i" << imag <<endl;
else
cout << real << " + i(" << imag <<")"<<endl;
}
};
int main() {
ComplexNum comp1(15, -2), comp2(5, 10);
cout<<"这两个补码是："<<endl;
comp1.print();
comp2.print();
cout<<"The result of the subtraction is: ";
ComplexNum comp3 = comp1 - comp2;
comp3.print();
}输出结果
这两个补码是： 15 + i(-2) 5 + i10 The result of the subtraction is: 10 + i(-12)
在上述程序中，定义了ComplexNum类，该类具有分别用于复数的实部和虚部的变量real和imag。构造函数ComplexNum用于初始化real和imag的值。它还包含默认值0。这在以下代码段中显示-
class ComplexNum {
private:
int real, imag;
public:
ComplexNum(int r = 0, int i =0) {
real = r;
imag = i;
}
}作为重载运算符的函数包含关键字运算符，后跟-，因为这是被重载的运算符。该函数将两个复数相减，结果存储在对象obj2中。然后，此值返回到ComplexNum对象comp3。
以下代码段演示了这一点-
ComplexNum operator - (ComplexNum const &obj1) {
ComplexNum obj2;
obj2.real = real - obj1.real;
obj2.imag = imag - obj1.imag;
return obj2;
}该print()函数打印复数的实部和虚部。如下所示。
void print() {
if(imag>=0)
cout << real << " + i" << imag <<endl;
else
cout << real << " + i(" << imag <<")"<<endl;
}