如何按照Java中最长到最短的模式按长度对字符串数组进行排序
首先，让我们创建字符串数组：
String[] strArr = { "ABCD", "AB", "ABCDEFG", "ABC", "A", "ABCDE", "ABCDEF", "ABCDEFGHIJ" }现在，从最长到最短的模式，例如ABCDEFGHIJ，ABCDEFG，ABCDEF等；获取两个字符串数组的长度，并像这样工作：
Arrays.sort(strArr, (str1, str2) → str2.length() - str1.length());
以下是在Java中按最长到最短模式对字符串数组进行排序的示例：
示例
import java.util.Arrays;
public class Demo {
public static void main(String[] args) {
String[] strArr = { "ABCD", "AB", "ABCDEFG", "ABC", "A", "ABCDE", "ABCDEF", "ABCDEFGHIJ" };
System.out.println("Sorting array on the basis of their lengths (longest to shortest) = ");
Arrays.sort(strArr, (str1, str2) → str2.length() - str1.length());
Arrays.asList(strArr).forEach(System.out::println);
}
}输出结果
Sorting array on the basis of their lengths (longest to shortest) = ABCDEFGHIJ ABCDEFG ABCDEF ABCDE ABCD ABC AB A
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