C ++程序检查字符串的第一个和最后一个字符是否相等

2024-05-01 08:17:05 353

示例

Input-: study Output-: not equal As the starting character is ‘s’ and the end character of a string is ‘y’ Input-: nitin Output-: yes it have first and last equal characters As the starting character is ‘n’ and the end character of a string is ‘n’

下面使用的方法如下-

输入字符串并存储在字符串数组中。

使用length()函数计算字符串的长度

检查字符串数组的第一个和最后一个元素，如果相等，则返回1，否则重新运行-1

打印结果输出

算法

Start
Step 1-> declare 检查第一个和最后一个字符是否相等的函数
   int check(string str)
   set int len = str.length()
      IF (len < 2)
         return -1
      End
      If (str[0] == str[len - 1])
         return 1
      End
      Else
         return 0
      End
Step 2->Int main()   declare string str = "nhooo"
   set int temp = check(str)
   If (temp == -1)
      Print “enter valid input"
   End
   Else if (temp == 1)
      Print "yes it have first and last equal characters"
   End
   Else
      Print "Not equal”
Stop

示例

#include<iostream>
using namespace std;
//检查第一个和最后一个字符是否相等的函数
int check(string str) {
   int len = str.length();
   if (len < 2)
      return -1;
   if (str[0] == str[len - 1])
      return 1;
   else
      return 0;
}
int main() {
   string str = "nhooo";
   int temp = check(str);
   if (temp == -1)
      cout<<"enter valid input";
   else if (temp == 1)
      cout<<"yes it have first and last equal characters";
   else
      cout<<"Not equal";
}

输出结果

如果我们运行以上代码，它将在输出后产生

yes it have first and last equal characters

C ++程序检查字符串的第一个和最后一个字符是否相等

示例

算法

示例

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