计算Modified Knight在C ++中可以到达的所有可能位置
在本教程中，我们将讨论一个程序，以查找ModifiedKnight可以到达的可能位置。
为此，我们将提供一个8*8的棋盘。我们的任务是找到“改良骑士”可以按照给定步骤数捕获的位置数。
示例
#include <bits/stdc++.h>
using namespace std;
//寻找职位
void findSteps(int current_row, int current_column,int curr, int board_size, int steps,int* visited){
//边界检查
if (current_row >= board_size || current_row < 0
|| current_column >= board_size || current_column < 0
|| curr > steps) {
return;
}
if (curr == steps) {
*((visited + (current_row)*board_size) + current_column) = 1;
return;
}
findSteps(current_row - 2, current_column - 1,curr + 1, board_size, steps, visited);
findSteps(current_row - 2, current_column + 1,curr + 1, board_size, steps, visited);
findSteps(current_row - 1, current_column - 2,curr + 1, board_size, steps, visited);
findSteps(current_row - 1, current_column - 1,curr + 1, board_size, steps, visited);
findSteps(current_row - 1, current_column + 1,curr + 1, board_size, steps, visited);
findSteps(current_row - 1, current_column + 2,curr + 1, board_size, steps, visited);
findSteps(current_row + 1, current_column - 2,curr + 1, board_size, steps, visited);
findSteps(current_row + 1, current_column - 1,curr + 1, board_size, steps, visited);
findSteps(current_row + 1, current_column + 1,curr + 1, board_size, steps, visited);
findSteps(current_row + 1, current_column + 2,curr + 1, board_size, steps, visited);
findSteps(current_row + 2, current_column - 1,curr + 1, board_size, steps, visited);
findSteps(current_row + 2, current_column + 1,curr + 1, board_size, steps, visited);
return;
}
int countSteps(int current_row, int current_column,int board_size, int steps){
int visited[board_size][board_size];
for (int i = 0; i < board_size; i++) {
for (int j = 0; j < board_size; j++) {
visited[i][j] = 0;
}
}
int answer = 0;
findSteps(current_row, current_column, 0,board_size, steps, (int*)visited);
for (int i = 0; i < board_size; i++) {
for (int j = 0; j < board_size; j++) {
if (visited[i][j] == 1) {
answer++;
}
}
}
return answer;
}
int main(){
int board_size = 8, steps = 1;
int current_row = 4, current_column = 4;
cout << countSteps(current_row, current_column,board_size, steps);
return 0;
}输出结果
12