MySQL ORDER BY ASC并在底部显示NULL？
为此，将CASE语句与ORDERBY一起使用。让我们首先创建一个表-
mysql> create table DemoTable1937 ( Name varchar(20) );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable1937 values('Chris');
mysql> insert into DemoTable1937 values(NULL);
mysql> insert into DemoTable1937 values('Adam');
mysql> insert into DemoTable1937 values('John');
mysql> insert into DemoTable1937 values('');
mysql> insert into DemoTable1937 values(NULL);
mysql> insert into DemoTable1937 values('Bob');使用select语句显示表中的所有记录-
mysql> select * from DemoTable1937;
这将产生以下输出-
+-------+ | Name | +-------+ | Chris | | NULL | | Adam | | John | | | | NULL | | Bob | +-------+ 7 rows in set (0.00 sec)
这是对ORDERBYASC的查询，并在底部显示NULL：
mysql> select * from DemoTable1937 order by case when Name IS NULL then 100 when Name='' then 101 else 103 end desc , Name asc;
这将产生以下输出-
+-------+ | Name | +-------+ | Adam | | Bob | | Chris | | John | | | | NULL | | NULL | +-------+ 7 rows in set (0.00 sec)