MySQL查询以选择日期> =当前日期-3周？
使用DATE_SUB()的概念。让我们首先创建一个表-
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, ArrivalDate datetime );
注意：假设当前日期为2019-06-08
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable(ArrivalDate) values('2019-05-15');
mysql> insert into DemoTable(ArrivalDate) values('2019-06-08');
mysql> insert into DemoTable(ArrivalDate) values('2019-05-20');
mysql> insert into DemoTable(ArrivalDate) values('2019-05-12');使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
输出结果
+----+---------------------+ | Id | ArrivalDate | +----+---------------------+ | 1 | 2019-05-15 00:00:00 | | 2 | 2019-06-08 00:00:00 | | 3 | 2019-05-20 00:00:00 | | 4 | 2019-05-12 00:00:00 | +----+---------------------+ 4 rows in set (0.00 sec)
这是选择日期的查询，该日期大于当前日期-3周-
mysql> select ArrivalDate from DemoTable where ArrivalDate> DATE_SUB(curdate(),INTERVAL 3 WEEK);
输出结果
+---------------------+ | ArrivalDate | +---------------------+ | 2019-06-08 00:00:00 | | 2019-05-20 00:00:00 | +---------------------+ 2 rows in set (0.00 sec)