在C ++中用星号替换单词
该程序的目的是通过使用c++编程代码用字符串中的星号替换特定的单词。向量和字符串类作文的基本功能对达到预期效果起关键作用。算法如下：
算法
START Step-1: Input string Step-2 Split the string into words and store in array list Step-3: Iterate the loop till the length and put the asterisk into a variable Step-4: Traverse the array foreah loop and compare the string with the replaced word Step-5: Print END
现在，基于该算法，下面的代码被提取出来。在这里，strtok()字符串方法将字符串拆分，并返回向量类的数组列表类型。
示例
#include <cstring>
#include <iostream>
#include <vector>
#include <string.h>
//分割字符串的方法
std::vector<std::string> split(std::string str,std::string sep){
char* cstr=const_cast<char*>(str.c_str());
char* current;
std::vector<std::string> arr;
current=strtok(cstr,sep.c_str());
while(current!=NULL){
arr.push_back(current);
current=strtok(NULL,sep.c_str());
}
return arr;
}
int main(){
std::vector<std::string> word_list;
std::cout<<"string before replace::"<<"Hello ajay yadav ! you ajay you are star"<<std::endl;
std::cout<<"word to be replaced::"<<"ajay"<<std::endl;
word_list=split("Hello ajay yadav ! you ajay you are star"," ");
std::string result = "";
//创建一个星号的检查器
// "*" text of the length of censor word
std::string stars = "";
std::string word = "ajay";
for (int i = 0; i < word.length(); i++)
stars += '*';
//遍历我们的列表
//提取的单词
int index = 0;
for (std::string i : word_list){
if (i.compare(word) == 0)
//将审查的单词更改为
//创建星号检查器
word_list[index] = stars;
index++;
}
//加入单词
for (std::string i : word_list){
result += i + ' ';
}
std::cout<<"output::"<<result;
return 0;
}
}从上面的代码中可以看出，所有字符串操作代码都被捆绑到retrieveChar()方法中，随后该调用被传递给程序main()执行。
输出结果
String before replace::Hello ajay yadav ! you ajay you are star Word to be replaced::ajay Output::Hello **** yadav ! you **** you are star