C#中的Math.Min()方法
C#中的Math.Min()方法用于返回两个指定数字中的较大者。此方法适用于Double，Decimal，Int16，Int32等数字。
语法
以下是语法-
public static ulong Min (ulong val1, ulong val2); public static uint Min (uint val1, uint val2); public static ushort Min (ushort val1, ushort val2); public static float Min (float val1, float val2); public static byte Min (byte val1, byte val2); public static long Min (long val1, long val2);
示例
现在让我们看一个实现Math.Min()方法的示例-
using System;
public class Demo {
public static void Main(){
byte val1 = 10, val2 = 15;
decimal val3 = 1000M, val4 = 1500M;
double val5 = 15.896745, val6 = 25.676843;
short val7 = 20, val8 = 30;
Console.WriteLine("Minimum Value from two byte values = "+Math.Min(val1, val2));
Console.WriteLine("Minimum Value from two decimal values = "+Math.Min(val3, val4));
Console.WriteLine("Minimum Value from two double values = "+Math.Min(val5, val6));
Console.WriteLine("Minimum Value from two short values = "+Math.Min(val7, val8));
}
}输出结果
这将产生以下输出-
Minimum Value from two byte values = 10 Minimum Value from two decimal values = 1000 Minimum Value from two double values = 15.896745 Minimum Value from two short values = 20
示例
我们来看另一个实现Math.Min()方法的示例-
using System;
public class Demo {
public static void Main(){
int val1 = 10, val2 = 15;
float val3 = 12.8f, val4 = 25.6f;
Console.WriteLine("Minimum Value from two int values = "+Math.Min(val1, val2));
Console.WriteLine("Minimum Value from two float values = "+Math.Min(val3, val4));
}
}输出结果
这将产生以下输出＆minuns;
Minimum Value from two int values = 10 Minimum Value from two float values = 12.8
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