MongoDB查询以聚合替换值？
与$literal运算符一起使用聚合框架。首先让我们创建一个包含文档的集合-
> db.replaceValueDemo.insertOne(
{
_id : 100,
"EmployeeName" :"Chris",
"EmployeeOtherDetails": {
"EmployeeDesignation" : "HR",
"EmployeeAge":27
}
}
);
{ "acknowledged" : true, "insertedId" : 100 }
> db.replaceValueDemo.insertOne(
{
_id : 101,
"EmployeeName" :"David",
"EmployeeOtherDetails": {
"EmployeeDesignation" : "Tester",
"EmployeeAge":26
}
}
);
{ "acknowledged" : true, "insertedId" : 101 }以下是在find()方法的帮助下显示集合中所有文档的查询-
> db.replaceValueDemo.find().pretty();
这将产生以下输出-
{
"_id" : 100,
"EmployeeName" : "Chris",
"EmployeeOtherDetails" : {
"EmployeeDesignation" : "HR",
"EmployeeAge" : 27
}
}
{
"_id" : 101,
"EmployeeName" : "David",
"EmployeeOtherDetails" : {
"EmployeeDesignation" : "Tester",
"EmployeeAge" : 26
}
}以下是替换值的查询-
> db.replaceValueDemo.aggregate([{
"$project": {
"_id": 1,
"EmployeeOtherDetails": {
EmployeeAge: 1,
EmployeeDesignation : { $literal: "Developer" }
}
}
}]);这将产生以下输出-
{ "_id" : 100, "EmployeeOtherDetails" : { "EmployeeAge" : 27, "EmployeeDesignation" : "Developer" } }
{ "_id" : 101, "EmployeeOtherDetails" : { "EmployeeAge" : 26, "EmployeeDesignation" : "Developer" } }热门推荐
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