Java中AbstractSequentialList的indexOf()方法
该indexOf()方法从AbstractList类继承。它用于返回此列表中指定元素的首次出现的索引。如果列表为空，则返回-1。
语法如下-
public int indexOf(Object ele)
在这里，ele是您想要为其索引的元素。
要使用Java中的AbstractSequentialList类，您需要导入以下包-
import java.util.AbstractSequentialList;
以下是indexOf()在Java中实现AbstractSequentialList方法的示例-
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(110);
absSequential.add(320);
absSequential.add(400);
absSequential.add(550);
absSequential.add(600);
absSequential.add(700);
absSequential.add(900);
System.out.println("Elements in the AbstractSequentialList = "+absSequential);
System.out.println("Elements in the AbstractSequentialList = "+absSequential.indexOf(550));
}
}输出结果
Elements in the AbstractSequentialList = [110, 320, 400, 550, 600, 700, 900] Elements in the AbstractSequentialList = 3
让我们看看另一个不存在元素的示例-
示例
import java.util.LinkedList;
import java.util.AbstractSequentialList;
public class Demo {
public static void main(String[] args) {
AbstractSequentialList<Integer> absSequential = new LinkedList<>();
absSequential.add(110);
absSequential.add(320);
absSequential.add(400);
absSequential.add(550);
absSequential.add(600);
absSequential.add(700);
absSequential.add(900);
System.out.println("Elements in the AbstractSequentialList = "+absSequential);
System.out.println("Elements in the AbstractSequentialList = "+absSequential.indexOf(10));
}
}输出结果
Elements in the AbstractSequentialList = [110, 320, 400, 550, 600, 700, 900] Elements in the AbstractSequentialList = -1