C#中的Decimal.ToInt32()方法
C#中的Decimal.ToInt32()方法用于将指定的Decimal的值转换为等效的32位带符号整数。
语法
以下是语法-
public static int ToInt32 (decimal val);
上面的Val是要转换的十进制数。
示例
现在让我们看一个实现Decimal.ToInt32()方法的示例-
using System;
public class Demo {
public static void Main(){
Decimal val1 = 0.001m;
Decimal val2 = 1.000m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
int res1 = Decimal.ToInt32(val1);
int res2 = Decimal.ToInt32(val2);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
}
}输出结果
这将产生以下输出-
Decimal 1 = 0.001 Decimal 2 = 1.000 32-bit signed integer (value1) (Decimal to signed integer) = 0 32-bit signed integer (value1) (Decimal to signed integer) = 1
示例
现在让我们来看另一个实现Decimal.ToInt32()方法的示例-
using System;
public class Demo {
public static void Main(){
Decimal val1 = -3.578m;
Decimal val2 = 9.352m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
int res1 = Decimal.ToInt32(val1);
int res2 = Decimal.ToInt32(val2);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
}
}输出结果
这将产生以下输出-
Decimal 1 = -3.578 Decimal 2 = 9.352 32-bit signed integer (value1) (Decimal to signed integer) = -3 32-bit signed integer (value1) (Decimal to signed integer) = 9