如何从MySQL列中的前20个字符之后选择所有字符？
让我们首先创建一个表-
mysql> create table DemoTable ( Title text );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable values('C is a good programming language to start');
mysql> insert into DemoTable values('Java is good with data structure and algorithm');
mysql> insert into DemoTable values('Coding is very important');使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
这将产生以下输出-
+------------------------------------------------+ | Title | +------------------------------------------------+ | C is a good programming language to start | | Java is good with data structure and algorithm | | Coding is very important | +------------------------------------------------+ 3 rows in set (0.00 sec)
以下是查询以选择前20个字符之后的所有字符-
mysql> select substring(Title from 20) from DemoTable;
这将产生以下输出-
+-----------------------------+ | substring(Title from 20) | +-----------------------------+ | ming language to start | | ata structure and algorithm | | rtant | +-----------------------------+ 3 rows in set (0.00 sec)