在C#中转置矩阵

2024-04-22 13:02:05 331

矩阵的转置会使矩阵在对角线上翻转，从而使行元素位于列上，而列元素位于行上。

例如-

Matrix before Transpose:

123
456
789

Matrix after Transpose:
147
258
369

让我们看一个用C#实现矩阵转置的示例-

示例

using System;
public class Demo {
   public static void Main() {
      int i, j, m, n;
      int[, ] arr1 = new int[30, 30];
      int[, ] arr2 = new int[30, 30];

      Console.Write("\nEnter the number of rows and columns of the matrix :\n");
      Console.Write("Rows entered = ");
      m = Convert.ToInt32(Console.ReadLine());

      Console.Write("Columns entered = ");
      n = Convert.ToInt32(Console.ReadLine());

      Console.Write("Set elements in the matrix...\n");
      for (i = 0; i < m; i++) {
         for (j = 0; j < n; j++) {
            Console.Write("\n [{0}],[{1}] : ", i, j);
            arr1[i, j] = Convert.ToInt32(Console.ReadLine());
         }
      }

      Console.Write("\n\nMatrix before Transpose:\n");
      for (i = 0; i < m; i++) {
         Console.Write("\n");
         for (j = 0; j < n; j++)
         Console.Write("{0}\t", arr1[i, j]);
      }

      for (i = 0; i < m; i++) {
         for (j = 0; j < n; j++) {

            arr2[j, i] = arr1[i, j];
         }
      }

      Console.Write("\n\nMatrix after Transpose: ");
      for (i = 0; i < m; i++) {
         Console.Write("\n");
         for (j = 0; j < n; j++) {
            Console.Write("{0}\t", arr2[i, j]);
         }
      }
      Console.Write("\n\n");
   }
}

运行以上程序将产生以下结果。在这里，将输入用户的值，以获取行数和列数以及矩阵的元素-

Enter the number of rows and columns of the matrix :3 3
Rows entered = 3
Columns entered 3
Set elements in the matrix...

[0],[0] : 1
[0],[1] : 2
[0],[2] : 3
[1],[0] : 4
[1],[1] : 5
[1],[2] : 6
[2],[0] : 7
[2],[1] : 8
[2],[2] : 9

Matrix before Transpose:

123
456
789

Matrix after Transpose:
147
258
369

在C#中转置矩阵

示例

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