Java程序将数字分为较小的随机整数
我们在这里考虑了数字10，该数字将分为8个带有Random类的随机整数。我们设置为HashSet集合的数字-
HashSet<Integer>set = new HashSet<Integer>(); set.add(0); set.add(0); set.add(0); set.add(number);
现在使用nextInt获取下一个随机整数-
intarrSize = parts + 1;
while (set.size() < arrSize) {
set.add(1 + randNum.nextInt(number - 1));
}
Integer[] dividers = set.toArray(new Integer[arrSize]);
Arrays.sort(dividers);
int[] res = new int[parts];
for(int i = 1, j = 0; i < dividers.length; ++i, ++j) {
res[j] = dividers[i] - dividers[j];
}示例
import java.util.Arrays;
import java.util.HashSet;
import java.util.Random;
public class Demo {
public static Random randNum = new Random();
public static int[] DemoFunc(int number, int parts) {
HashSet<Integer>set = new HashSet<Integer>();
set.add(0);
set.add(0);
set.add(0);
set.add(number);
int arrSize = parts + 1;
while (set.size() < arrSize) {
set.add(1 + randNum.nextInt(number - 1));
}
Integer[] dividers = set.toArray(new Integer[arrSize]);
Arrays.sort(dividers);
int[] res = new int[parts];
for(int i = 1, j = 0; i < dividers.length; ++i, ++j) {
res[j] = dividers[i] - dividers[j];
}
return res;
}
public static void main(String[] args) {
System.out.println(Arrays.toString(DemoFunc(10, 8)));
}
}输出结果
[1, 1, 2, 2, 1, 1, 1, 1]